Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
189 views
in Chemistry by (91.3k points)
closed by
एक धातु (परमाणु भार = 50) की क्रिस्टल संरचना bcc तथा घनत्व 5.96 gm//cm^3` है, तो उसके इकाई सेल की कोर लम्बाई की गणना कीजिए|

1 Answer

0 votes
by (90.6k points)
selected by
 
Best answer
दिया गया है - `M=50, Z = 2 (b.c.c.),`
`prop=5.96 gm//cm^3, N_0= 6.023 xx 10^23`
एवोगेड्रो इकाई सेल का आयतन `(a^3) = (M.Z)/(prop. N_0)`
`a^3=(50xx2)/(5.96xx6.023xx10^23)`
`a^3=2.78 xx10^(-23) cm^3`
इकाई सेल की कोर लम्बाई (a)
`=3.04 xx10^(-8)cm= 304 pm`.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...