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सोडियम धातु (परमाणु भार = 23 ) की क्रिस्टल संरचना b.c.c. तथा इकाई सेल की कोर लम्बाई 0.424 nm है, तो सोडियम के घनत्व एवं परमाणु त्रिज्या की गणना कीजिए|

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दिया गया है - `M= 23, Z = 2 (b.c.c.), N_0= 6.023xx 10^23,a = 0.424 nm = 4.24 xx10^(-8) cm`.
`a= 4.24 xx 10^(-8) cm`
`a^3 = 76.22 xx 10^(-24) cm^3`
`a^3 = 7.622 xx 10^(-23) cm^3`
घनत्व `(prop)=(M.Z)/(a^3. N_0)`
घनत्व `(a^3)=(23xx2)/(7.62xx10^(-23)xx6.023xx 10^23)`
`=1.002 gm// cm^3`.
bcc प्रकार के इकाई सेल में कोर लम्बाई (a) तथा परमाणु त्रिज्या (r) के मध्य संबंध निम्नानुसार है -
`r=(sqrt3a)/4, r=0.433 a`
`r=0.433xx 0.433 a`
`r= 0.433 xx0.424 nm `
`=0.1836 nm`.

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