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in Chemistry by (40.5k points)

The order of decreasing electron affinity of the electronic configurations

I. 1s2, 2s2, 2p6, 3s2, 3p5

II. 1s2, 2s2, 2p3

III. 1s2, 2s2, 2p5

IV. 1s2, 2s2, 2p6, 3s2 ,3P4

(a) II, IV, III, I

(c) I, III, IV, II

(b) I, II, III, IV

(d) I, III, II, IV

2 Answers

+1 vote
by (44.9k points)
selected by
 
Best answer

Correct Option (d) I, III, II, IV

Explanation:

The given electronic configuration of elements corresponds to

Electron affinity genergally increases from left to right on moving along a period which it decreases down the group.

But electron affinities of groups 18 and 15 elements are more positive [less electronegative] than 16 group elements due to stable electronic configuration. While group 17 elements have highest value of electron affinity [more negative].

Though F and Cl belongs to group 17 elements but Cl possesses larger electron affinity than F although F is more electronegative than Cl because F has very small size due to which the additional electron repels 2p electrons.

This results in less evolution of energy in the formation of F- ion. Hence, the decreasing order of affinity for the given electronic configuration is

i > iii > ii > iv

(Cl) (F) (N) (Ar)

+1 vote
by (10.9k points)
option (d) is correct

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