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निर्वात में प्रकाश के चलने कि दिशा `vecExxvecB` कि ओर होती है। ऊपर के प्रश्न में `vecE` तथा `vecB` के व्यंजक दिए गए है। प्रकाश के चलने कि दिशा में इकाई वेक्टर निकाले।

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`vecExxvecB=(10hati+5hatj-3hatk)xx(2hati-7hatj-5hatk)`
`=10hatixx(2hati-7hatj-5hatk)+5hatjxx(2hati-7hatj-5hatk)-3hatkxx(2hati-7hatj-5hatk)`
`=-70hatk-50(-hatj)+10(-hatk)-25hati-6hatj+21(-hati)=-46hati+44hatj-80hatk.`
इस दिशा में इकाई वेक्टर
`=(vecExxvecB)/(|vecExxvecB|)=(-46hati+44hatj-80hatk)/(sqrt(46^(2)+44^(2)+80^(2)))~~(-23hati+22hatj-40hatk)/(51).`

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