Question

The maximum number of electrons that can have principal quantum number n = 3 & spin quantum number `m_(s)=-(1)/(2)` is :-
A. 9
B. 18
C. 32
D. 6

Answer 1

Correct Answer - C
n = 3, then number of orbitals `= n^(2)= 9`
each obital has one electrons with m, `= -(1)/(2)`