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In question number 45, what will be the electric field at centre O, if the charge from one of the corners (say A) is removed?
A. `q/(4piepsilon_(0)r^(2))` along OA
B. `(2q)/(4piepsilon_(0)r^(2))` along OB
C. `(q^(2))/(4piepsilon_(0)r^(2))` along OC
D. `(2q)/(4piepsilon_(0)r^(2))` along OA

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Best answer
Correct Answer - A
When a charge q from corner A is removed, electric field at O is `E_(1)=q/(4piepsilon_(0)r^(2)` along OA

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