The solution of 1/x . dy/dx = tan^-1 is…… ​

Question

The solution of \(\frac{1}{x} .\frac{dy}{dx} = \) tan^-1 is……

(a) \(\cfrac{x^2tan^{-1}x}{2}\) + c = 0

(b) x tan^-1x + c = 0 

(c) x – tan^-1x = c 

(d) y = \(\cfrac{x^2tan^{-1}x}{2}\) - 1/2 (x-tan^-1x) + c

Answer 1

Correct option is: (d) y = \(\cfrac{x^2tan^{-1}x}{2}\) - 1/2 (x-tan^-1x) + c