(x^2/a^2) - (y^2/b^2) = 1 is a solution of……..

Question

\(\cfrac{x^2}{a^2} - \cfrac{y^2}{b^2} = 1\) is a solution of……..

(a) \(\cfrac{d^2y}{dx^2} +yx +\left(\cfrac{dy}{dx}\right)^2 =0\)

(b) xy + 2\(\left(\cfrac{dy}{dx}\right)^2\) - y\(\cfrac{dy}{dx}\) = 0

(c) y\(\cfrac{d^2y}{dx^2}\) +  2\(\left(\cfrac{dy}{dx}\right)^2\) + y = 0

(d) xy\(\cfrac{dy}{dx}\) + y\(\cfrac{d^2y}{dx^2}\) = 0

Answer 1

Correct option is: (b) xy + 2\(\left(\cfrac{dy}{dx}\right)^2\) - y\(\cfrac{dy}{dx}\) = 0

Equation (1), (2) and (3) are consistent