C3H4 + 4O2 \(\overset{Combustion}{\longrightarrow}\) 3CO2 + 2H2O
1 mole + 4 mole \(\longrightarrow\) 3 mole + 2 mole
on complete combustion of 1 mole of C3H4 gave 2 mole of water.
molecular weight of H2O = 18g/mole
\(\therefore\) Number of gram H2O produced = (2 x 18) g = 36 g
Hence, on complete combustion of 1 mole of C3H4 produced 36 g H2O.