Correct Answer - B
Vapour pressure of pure water at boiling point =1 atm = 1.013 bar
Vapour pressure of solution `(p_s)`=1.004 bar
Let mass of solution = 100 g
Mass of solute=2 g
Mass of solvent = 100-2= 98 g
`(p^@-p_s)/p^@=n_2/(n_1+n_2)=n_2/n_1 =(W_2//M_2)/(W_1//M_1) ( because n_2 lt lt lt n_1)`
`(1.013-1.004)/1.013=2/M_2xx18/98`
or `M_2=(2xx18)/98xx(1.013)/0.009 = 41.35 g mol^(-1)`