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Acidified potassium dichromate reacts with potassium iodide and oxidiese it to `I_2`. What is the oxidation state of chromium in the products of the reaction?
A. `+4`
B. `+6`
C. `+3`
D. `+2`

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Correct Answer - C
During the reaction `K_2Cr_2O_7` is converted to `Cr_2(SO_4)_3`
`K_2Cr_2O_7+7H_2SO_4+6KI to 4K_2SO_4+Cr_2(SO_4)_3+7H_2O+3I_2`
In `Cr_2(SO_4)_3," O.S. of Cr is "+3`

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