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An aqueous solution of `2%` non volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molecular mass of the solute ?

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Relative lowering of vapour pressure `(P_(0)-P_(s))/(P_(0))=(n_(s))/(n_(0))`
`P_(0)=1.013" bar",P_(s)=1.004" bar"`
w = 2 gms W = 98 gms
M = 18 m = ?
`(1.013-1.004)/(1.013)=(2xx18)/(m xx98)`
`m=(2xx18xx1.013)/(0.009xx98)=(36xx1.013)/(0.882)`
`=41.35" gms"//"mole".`

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