Resistance of a conductivity cell filled with `0.1 mol L ^(-1)` KCl solution is `100 Omega.` If the resistance of the same cell when filled with `0.02 mol L^(-1)` KCl solution is `520 Omega,` calculate the conductivity and molar conductivity of `0.02 mol L^(-1)KCl` solution. The conductivity of `0.1 mol L^(-1)` KCl solutin is `1.29` S/m.