Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
117 views
in Physics by (97.1k points)
closed by
The mass of the earth is 81 times that of the moon and the radius of the earth is 3.5 times that of the moon. The ratio of the escape velocity on the surface of earth to that on the surface of moon will be
A. 0.2
B. 2.57
C. 4.81
D. 0.39

1 Answer

0 votes
by (97.1k points)
selected by
 
Best answer
Correct Answer - C
Esacpe velocity `v_(e )=sqrt(2GM)/(R )`
`therefore (v_(e ))/(v_(m))=sqrt(M_(e )R_(m))/(M_(m)R_(e))=sqrt(81)/(3.5)=4.81`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...