Correct Answer - c
For fundamental mode in open pipe,
and `v_(0)=v/21...(i)`
For third harmonic in closed pipe
`v=(2n+1)v/(4l)`
`n=1=(3v)/(4l)`
From Eqs. (i) and (ii), we have
`v-v_(0)=100` (given)
`rArr 3/2. v-v_(0)=100 ...(iii)`
`therefore v/2=100`
` rArr v_(0)=200 ` hz