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+1 vote
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in NEET by (2.4k points)
A particle moving along a  circular  path has equal magnitude of linear and angular  accelaration. The diameter of the path is

A)1

B)2

C)pie

D)2 pie

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1 Answer

0 votes
by (10.9k points)
Angular acceleration  (A)× radius(r)= linear acceleration (a)

Given A = a we get r=1

So diameter (d) =2

Option (B) is accepted

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