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in Indefinite Integral by (32.3k points)
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\(\int \frac{log(3x)}{x\,log(9x)}.dx =\)

log(3x)/x log (9x) .dx =

(a) log(3x) – log(9x) + c 

(b) log(x) – (log 3) . log(log 9x) + c 

(c) log 9 – (log x) . log(log 3x) + c 

(d) log(x) + log(3) . log(log 9x) + c

1 Answer

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Best answer

Correct answer is (b) log(x) – (log 3) . log(log 9x) + c

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