36 A student connects 10 dry cells each of emf \( E \) and internal resistance \( r \) in series, but by mistake the one cell gets wrongly connected. Then net emf and net internal resistance of the combination will be
\( \begin{array}{ll}\text { a } & 8 E , 8 r \\ \text { b } & 10 E , 10 r \\ \text { c } & 8 E , 10 r \\ \text { d } & 8 E , r / 10\end{array} \)