Let the Lower class limit and upper class limit of the class mark 5 be x and y respectively.
Class Mark = \(\frac{Lower\, class\, limt \,+\,Upper\, class\, limt \,}{2}\)
\(\therefore\) \(5 =\frac{x\,+\,y}{2}\)
∴x + y = 10
Here, class width = 15 – 5 = 10
But, Class width = Upper class limit – Lower class limit
∴ y – x = 10
∴ -x + y = 10 …(ii)
Adding equations (i) and (ii),
x+ y = 10
-x + y = 10
∴ 2y = 20
∴ y = 10
Substituting y = 10 in equation (i),
∴ x + 10 = 10
∴ x = 0
∴ class with class-mark 5 is 0 – 10
Similarly, we can find the remaining classes.
∴ frequency table taking inclusive and exclusive classes.