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Find the
(a) maximum frequency, and

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Given voltage `V = 30 " kV "= 30xx10^(3)V, e = 1.6xx10^(-19) C, h = 6.63xx10^(-34)j-s`
`C = 3xx10^(8)m//s`
Maximum frequency, `v=(eV)/(h)=(1.6xx10^(-19)xx30xx10^(3))/(6.63xx10^(_34))=7.24xx10^(18)Hz`

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