Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
85 views
in Chemistry by (96.8k points)
closed by
Oxygen is prepared by catalytic decomposition of potassium chlorine `(KClO_(3))`. Decomposition of potassium, chloride gives potassium chloride (KCl) and oxygen `(O_(2))`. How many moles and how many grams of `KClO_(3)` are required to produce 2.4 mole `O_(2)`?
A. `196.0`
B. `190.6`
C. `169.0`
D. `196.2`

1 Answer

0 votes
by (96.8k points)
selected by
 
Best answer
Correct Answer - A
The balanced equation is
`underset(underset(2xx(39+35.5+3xx16)=245"g")(2"mol"))(2KClO_(3)(s)+)20_(2)(g)rarr 2KCl(s) + underset(underset(2.4 "moles")(3 "mol"))(3O_(2))(g)`
`because` 3 moles of `O_(2)` Is produced by decomposition of `KClO_(3) = 245`g
`because 2.4` moles of `O_(2)` will be produced by the decompostion of ltb rgt `KClO_(3)=(245xx2.4)/3=196.0 "g"`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...