# An antifreeze solution is prepared from 222.6 g of ethylene glycol [C_(2)H_(4)(OH)_(2)] and 200 g of water. Calculate the molality of the soluti

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An antifreeze solution is prepared from 222.6 g of ethylene glycol [C_(2)H_(4)(OH)_(2)] and 200 g of water. Calculate the molality of the solution. If the density of the solution is 1.072g mL^(-1) then what shall be the molarity of the solution?
A. 9.10,17.95
B. 10.90,16.6
C. 12.04,17.95
D. 18.2,16.97

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"Molality"=("moles of solute (glycol)")/("kg of solvent")=(222.6)/(62)/0.200
=17.95" mol "kg^(-1)
"Total mass of solution"=222.6+200=422.6g
"Volume of solution"=("mass")/("density")=(422.6)/(1.072)mL=(0.4226)/(1.072)L
:."Molarity"=("moles of solute")/("litre")=(22.6//62)/(0.4226//11.072)=9.10M