Correct Answer - b
Angular speed of minute hand
`omega_(m)=360^(@)` per hour
`=(360x(pi)/(180))` per hour =`(2pi)/(3600)` rad/s
angular speed of second hand
`omega_(s)=360^(@)` per minute =`(2pi)/(60)` rad / s
`therefore` differnce between angular speeds of minute hand and second hand of a clock
`=omega_(m)-omega_(s)=(2pi)/(3600)-(2pi)/(60)=-(59pi)/(1800`
so difference between `omega_(m)` and `omega_(s)` is `(59pi)/(1800)` rad/s
