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Moment of inertia of a thin uniform rod rotating  about perpendicular axis  passing  through its centre is  I . If  the same rod is bent into a ring and moment  of inertia about its diameter  is I. Then the ratio I/ Iis 

A) 8/3( pie)2

B) 5/3(pie) square   

c) 3/ 2( pie) square 

 

D ) 2/3 (pie) square

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Solution........

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