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The potential energy of a 1 kg particle free to move along the x-axis is given by

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The potential energy of a 1 kg particle free to move along the x-axis is given by

v(x) = (x4/4 - x2/2)J

The total mechanical energy of the particle is 2 J. Then, the maximum speed (in ms-1) is

(a) 3/√2

(b) √2

(c) 1/√2

(d)  2

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Correct option (a) 3/√2

Explanation:

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