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Upon fully dissolving 2.0 g of a metal in sulfuric acid, 6.8 g of the metal sulfate is formed. The equivalent weigth of the metal is-
A. `13.6 g`
B. `20.0g`
C. `4.0g`
D. `10.0g`

1 Answer

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Best answer
Correct Answer - B
Equivalents of metal=Equivalents of metal sulphate
`("wt.of metal")/("Eq. wt. of metal")("wt. of metal sulphate")/("Eq. wt. metal sulphate")`
`(2)/(x)=(6.8)/(x +48)`
`6.8x=2x+96`
`4.8x=96`
`x=(96)/(4.8)=20`

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