Question

18 g of glucose, C₆H₁₂O₆ (Molar Mass = 180 g mol^-1) is dissolved in 1 kg of water in a sauce pan. At what temperature will this solution boil ? 

(K_b for water = 0.52 K kg mol^-1, boiling point of pure water = 373.15 K)

Answer 1

=> T_b - 373.15 = 0.52/10

=> T_b - 373.15 = 0.052K

=> T_b = 0.052 + 373.15

.^. . T_b = 373.202K