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+1 vote
84.1k views
in Physics by (56.2k points)

A circular loop of radius 0.3 cm lies parallel to a much bigger circular loop of radius 20cm .The centre of the small Ioop is on the axis of the bigger loop.The distance between their centres is 15 cm. If a current of 2.0 A flows through the smaller loop, then the flux linked with bigger loop is

(a) 9.2x10-11Wb (b) 6x10-11Wb (c) 3.3x10-11Wb (d) 6.6x10-9Wb

1 Answer

+4 votes
by (78.5k points)
selected by
 
Best answer

Correct Option(a) 9.2x10-11Wb

Explanation:

The magnetic field due to the bigger circular loop is

by (10 points)
Hello i have a question. Sir how can take smaller loop area if flux is being asked over the bigger loop? And in the denominator why have radius of bigger loop is considered if current is flowing in the samller loop?? Were you just concerned in having the correct option? Dont you the question is wrong as it should be the current flowing in bigger flux should have been asked over the samller loop??? Because we can't use this formula for the flux over the bigger loop as magnetic field wont be same everywhere on the area of the bigger loop....
by (49.1k points)
B is formed over the bigger loop so we have calculated B taking R of a bigger loop and in the second part magnetic flux  is created by the small loop so we have to take R of the smaller loop in calculating flux.

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