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+1 vote
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in Physics by (84.9k points)
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A 100 volt battery is connected across the series combination of the two capacitors of `4muF and 8muF`. The energy stored in the series combination is
A. `3/4xx10^(-2)J`
B. `4/3xx10^(-2)J`
C. 0.5J
D. 1 J

1 Answer

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Best answer
Correct Answer - B
`E=1/2C_(s)V^(2)=1/2((C_(1)C_(2))/(C_(1)+C_(2)))V^(2)`
`=(32xx10^(-6)xx10^(4))/(2xx12)=4/3xx10^(-2)J`

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