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An alternating current of rms value 5A, passes through a resistance of `24 Omega`. What is the maximum P.D. across the resister?
A. 17 V
B. 34 V
C. 170 V
D. 10 V

1 Answer

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Best answer
Correct Answer - C
Max P.D. = `I_(0) xx R = I_(rms) xx sqrt(2) xxR`
`=5sqrt(2) xx 24 = 170 V`.

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