Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
68 views
in Chemistry by (84.9k points)
closed by
The density of a solution prepared by dissolving 120 g of urea (mol. Mass=60 u) in 1000 g of water is 1.15 g/mL. The molarity if this solution is
A. 2.05 M
B. 0.50 M
C. 1.78 M
D. 1.02 M

1 Answer

0 votes
by (86.7k points)
selected by
 
Best answer
Correct Answer - A
Total mass of the solution = 1000 + 120 g =1120 g
:. Volume of the solution
`="mass"/"density"=(1120g)/(1.15 g mL^(-1)) = 974 mL `
Molarity of the solution
`(120//60)/974 xx 1000 M = 2.05 M.`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...