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Three resistors `2Omega, 4Omega and 5Omega` are combined in parallel. This combination is connected to a battery of emf 20V and negligible internal Resistance. The total current drawn from the battery is
A. 10A
B. 15A
C. 19A
D. 23A

1 Answer

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Best answer
Correct Answer - C
Potential fo 20V will be the same across each resistance current
`I_(1)=(V)/(R_(1))=(20)/(2)=10A`
`I_(2)=(V)/(R_(1))=(20)/(4)=5A`
`I_(3)=(V)/(R_(3))=(20)/(5)=4A`
Total current drawn from cicuit `O=I_(1)+I_(2)+I_(3)=10+5+4=19A`
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