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If values of `Lambda_(0)` of `NH_(4)Cl , NaOH and NaCl` are 130 , 127 and `109 Omega^(-1) cm^(2) eq^(-1)` respectively . The `Lambda_(NH_(4)OH)^(@)` in `Omega^(-1) cm^(2) eq^(-1)` is
A. 456
B. 238
C. 196
D. 22

1 Answer

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Correct Answer - B
`Lambda_(NH_(4)OH)^(@)= Lambda_(NH_(4)Cl)^(@) + Lambda_(NaOH)^(@) - Lambda_(NaCl)^(@)`
`= 130 + 217 - 109`
`= +238 Omega cm^(2) eq^(-1)`

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