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In double slit experiment using light of wavelength `600 nm`, the angular width of a fringe formed on a distant screen is `0.1^(@)`. What is the spacing between the two slits ?
A. `3.44xx10^(-4)m`
B. `1.54xx10^(-4)m`
C. `1.54xx10^(-3)m`
D. `1.44xx10^(-3)m`

1 Answer

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Best answer
Correct Answer - A
Angular width fo fringe,
`theta=0.1^(@)=0.1xx(pi)/(180)"rad" =(3.14)/(1800)"rad" `
` :. d=(lambda)/(theta)=(600xx10^(-9))/(3.14//1800)=3.44xx10^(-4) m`

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