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Hydrogen (1H1), deuterium (1H2), singly ionised helium (2He4)+ and doubly ionised lithium (3Li8)++ all have one electron around the nucleus. Consider an electron transition form n = 2 to n =1. If the wavelengths of emitted radiation are λ1λ2λ3 and λ4 a respectively for four elements, then approximately which one of the following is correct?

(a) 4λ1 = 2λ= 2λ3 = λ4

(b)  λ1 = 2λ= 2λ3 = λ4

(c)  λ1 = λ= 4λ3 = 9λ4

(d)  λ1 = λ= 3λ3 = 4λ4

1 Answer

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Best answer

Correct Option (c)  λ1 = λ= 4λ3 = 9λ4

Explanation:

For hydrogen atom, we get

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