Use app×
JEE MAIN 2024
JEE MAIN 2025 Foundation Course
NEET 2024 Crash Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
9.6k views
in Chemistry by (61.9k points)

For the first order decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data were obtained:

Experiment Time (s) Total pressure (atm)
1 0 35.0
2 720 63.0

Calculate the rate constant. The equation for the reaction is: 

(CH3)2 CHN = NCH(CH3)2  C6H14(g) + N2(g) 
[Given: log 3 = 0.4771; log 5 = 0.6990]

1 Answer

+2 votes
by (34.7k points)
selected by
 
Best answer

PA = 2P0 - Pt 

= (2 X 35) - 63

= 7

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...