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Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will be
A. 7.5 mol
B. 0.2 mol
C. 0.6 mol
D. 0.4 mol

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Correct Answer - C
`MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O`
`FeC_(2)O_(4)rarrFe^(2+)+C_(2)O_(4)^(2-)`
`Fe^(2+)rarrFe^(3+)+e^(-)`
`C_(2)O_(4)^(2-)rarr2CO_(2)+2e^(-)`
Since one mole of `FeC_(2)O_(4)` loses 3 moles of electrons whole one mole of `MnO_(4)^(-)` accepts five moles of electrons
Hence `KMnO_(4)` required to oxidize one mole of `FeC_(2)O_(4)=3//5 = 0.6` mol.

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