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A current of 0.4 ampere is passed for 30 minutes through a voltameter containing `CuSO_(4)` solution. The weight of Cu dpeosited will be
A. 3.18g
B. 0.318g
C. 0.296g
D. 0.150g

1 Answer

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Best answer
Correct Answer - C
`Q=1xxt=0.5xx30xx60=900C`
`Cu^(2+)+2e^(-)rarrCu`
`2xx96500C` deposit `Cu=63.5g`
`therefore 900C` will deposit Cu
`=(63.5)/(2xx96500)xx900=0.296g`

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