Question

The binding energy per nucleon of deuteron (₁H²) and helium nucleus (₂He⁴) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

(a) 13.9 MeV 

(b) 26.9 MeV

(c) 23.6 MeV 

(d) 19.2 MeV.

Answer 1

Correct Option (c) 23.6 MeV

Explanation:

The binding energy per nucleon of a deuteron (₁H²) =1.1 MeV

Total binding energy of one deuteron nucleus = 2 x 1.1 = 2.2 MeV

The binding energy per nucleon of helium (₂He⁴) = 7 MeV

Total binding energy = 4 x 7 = 28 MeV

Hence, energy released in the above process