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`50 mL` of `10 N H_(2)SO_(4), 25 mL` of `12 N HCI` and `40 mL` of `5N HNO_(3)` are mixed and the volume of the mixture is made 1000 mL by adding water. The normality of resulting solution will be
A. `1N`
B. `2N`
C. `3N`
D. `4N`

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Correct Answer - A
`N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3)=N_(4)V_(2)`
`10 N xx 50 mL +12 Nxx25 mL+5 Nxx40 mL`
`=N_(4)xx1000 mL`
(Volume of mixture = 1000 mL)
`N_(4) = (500+300+200)/(1000) N = 1N`

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