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Equal volumes of ethylene glycol (molar mass = 62) and water (molar mass = 18) are mixed. The depression in freezing point of water is (given `K_(f)` of water `= 1.86 K mol^(-1)` kg and specific gravity of ethylene glycol is 1.11)
A. `0.0033`
B. `3.33
C. `0.333`
D. `33.3`

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`M=DxxV`
M (Ethylene glycol) `= 1.11 xx upsilon`
M (water) `= 1.00 xx upsilon`
n(Ethylene glycol) = `(1.11 upsilon)/(62)` mol
`Delta T_(f)= K_(f)xx m=1.86 xx (1.11 upsilon)/(62)xx(1000)/(1.00 upsilon)`
`=(1.86xx1.11xx1000)/(62)=33.3`

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