Question

`6.02xx10^(20)` molecules of urea are present in 100 ml of its solution. The concentration of solution is :
A. `0.02M`
B. `0.01M`
C. `0.001M`
D. `0.1M`

Answer 1

Correct Answer - B
5.2 modal solution means 5.2 moles of the solute `(CH_(3)OH)` are present in 1000 g of water , i.e.
`(1000)/(18)=55.55` moles of water
`therefore` Mole fraction of `CH_(3)OH`
`=(5.2)/(5.2xx55.5)=0.086`