# A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The fre

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A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K.
A. 271 K
B. 273.15K
C. 269.07K
D. 277.23K

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DeltaT_(f)=(1000xxK_(f)xxW_(2))/(W_(1)xxM_(2))
DeltaT_(f) (cane sugar) = 273.15-271=2.15K
therefore2.15=(1000xxK_(f)xx5)/(95xx342)â€¦â€¦(i)
DeltaT_(f)("glucose")=(1000xxK_(f)xx5)/(95xx180)â€¦..(ii) Dividing (ii) by (i)
(DeltaT_(f)("glucose"))/(2.15)=(342)/(180)or DeltaT_(f)("glucose")=4.08^(@)
therefore freezing point glucose solution
=273.15-4.08=269.07K