Question

`DeltaG` for a reaction at `300 K` is `-16 kcal` and `DeltaH` is `-10 kcal`. The entropy of the reaction is
A. `20 cal deg^(-1)`
B. `86.6 cal deg^(-1)`
C. `166 cal deg^(-1)`
D. `100 cal deg^(-1)`

Answer 1

Correct Answer - A
`DeltaG=DeltaH-TDeltaS`
or `DeltaS=(DeltaH-DeltaG)/(T)=(-10-(-16))/(300)`
`=(6xx1000)/(300)=20cal deg^(-1)`