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in Chemistry by (6.2k points)

The kinetic energy of one gram mole of a gas at normal temperature and pressure is (R = 8.31 J/mole-K

(a) 0.56 x 104 J

(b) 1.3 x 102 J

(c) 2.7 x 102 J

(d) 3.4 x 103 J

1 Answer

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Best answer

Correct Option (d) 3.4 x 103 J

Explanation: 

E = 3/2RT = 3/2 x 8.31 x 273 = 3.4 x 103 Joule

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