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in Triangles by (34.5k points)
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In a ΔXYZ, if the internal bisector of ∠X meets YZ in P. Then

(A) XY/XZ = YP/PZ

(B) XY/PZ = XZ/YP

(C) XY/XZ = PZ/XP

(D) XZ/XY = YZ/YP

2 Answers

+1 vote
by (57.0k points)
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Best answer

Correct option is (A) XY/XZ = YP/PZ

The interior angle bisector theorem states that the angle bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

Given :\(\triangle XYZ \) in which XP is the internal bisector of \(\angle X\) and meets YZ at P.

\(\therefore\) \(\frac{YP}{PZ}=\frac{XY}{XZ}\)       (By internal bisector theorem)

\(\Rightarrow\) \(\frac{XY}{XZ} = \frac{YP}{PZ}\)

+1 vote
by (35.6k points)

Correct option is: (A) \(\frac{XY}{XZ}=\frac{YP}{PZ}\)

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