Correct option is (D) A’ ↔ A
In \(\triangle ABC\) & \(\triangle A’B’C’\)
\(A'\longleftrightarrow A\) (i.e., A' corresponds to A)
\(B'\longleftrightarrow B\)
\(C'\longleftrightarrow C\)
Hence, A' corresponds to A is symbolically denoted by \(A'\longleftrightarrow A.\)