Correct option is (C) SAS
\(\because\) Given that \(AB=DE\;\&\;AC=DF\)
and \(\angle BAC=\angle EDF\)
\(\therefore\) \(\frac{AB}{DE}=1\;\&\;\frac{AC}{DF}=1\)
\(\Rightarrow\) \(\frac{AB}{DE}=\frac{AC}{DF}\) ______________(1)
Now, in triangles \(\triangle ABC\;\&\;\triangle DEF\)
\(\angle BAC=\angle EDF\) (Given)
And \(\frac{AB}{DE}=\frac{AC}{DF}\) (From (1))
\(\therefore\) \(\triangle ABC\sim\triangle DEF\) (By SAS criterion of similarity)