Correct option is (D) 4
Given that \(\sqrt{15-x\sqrt{14}}=\sqrt8-\sqrt7\)
\(\Rightarrow\) \(15-x\sqrt{14}=(\sqrt8-\sqrt7)^2\) (By squaring both sides)
\(\Rightarrow\) \(15-x\sqrt{14}=8+7-2\sqrt8\times\sqrt7\) \((\because(a-b)^2=a^2+b^2-2ab\) Here \(a=\sqrt8\,\&\,b=\sqrt{7})\)
\(\Rightarrow\) \(15-x\sqrt{14}=15-4\sqrt{14}\)
\(\therefore\) x = 4 (By comparing)