Question

A tangent PA touches a circle with centre ‘O’ at A, then 

(A) ∠OPA = 90° 

(B) ∠POA = 90° 

(C) ∠OAP = 45° 

(D) ∠OAP = 90°

Answer 1

Correct option is: (D) ∠OAP = 90°

We know that the tangent is perpendicular to radius drawn through the point of contact.

Here, OA is radius drawn through the point of contact (A) of tangent (PA) and circle.

\(\therefore\) PA \(\perp\) OA

= \(\angle\)OAP = 90°

Answer 2

Correct option is: (D) ∠OAP = 90°